. A coin is tossed 400 times and outcomes are tail: 230, head : 170. Find the probability of getting each event.
Answers
Answer:
Step-by-step explanation:
We know,
Probability of an event = favourable outcomes/ total outcomes
So clearly,
Probability of getting a head =170/400
Probability of getting a tail = 230/400
Given,
A coin is tossed 400 times and outcomes are tail: 230, head : 170.
To find,
The probability of getting each event.
Solution,
We can simply solve this mathematical problem using the following process:
Mathematically,
The probability of occurrence of a favorable event = P (favorable event)
= (Total number of occurrence of the favorable event) / (Total number of occurrence of all possible events)
= (Total number of occurrence of the favorable event) / (Total number of trials)
(a) As per the given question;
The favorable event is the occurrence of a head.
Frequency of occurrence of the favourable event
= number of times head occured = 170
And, the total number of trials = total number of times the coin is tossed = 400
So, the probability of getting a head
= P (getting a head)
= (Total number of occurrence of the favorable event)/(Total number of trials)
= (170)/(400) = 0.425
(b) As per the given question;
The favorable event is the occurrence of a tail.
Frequency of occurrence of the favourable event
= number of times tail occured = 230
And, the total number of trials = total number of times the coin is tossed = 400
So, the probability of getting a tail
= P (getting a tail)
= (Total number of occurrence of the favorable event)/(Total number of trials)
= (230)/(400) = 0.575
Hence, the probability of getting a head and tail is equal to 0.425 and 0.575, respectively.