Question

A coin is tossed 500 times with the following frequencies
of two outcomes: Head: 240 times, Tail: 260 times.
find the probability of occurrence of (1) Head (1) Tail.​

Answer 1

probability of head = 0.48

probability of tail = 0.52

Answer 2

Answer:

0.48

0.52

Step-by-step explanation:

Given

• Coin is tosses 500 times.

Lets assume the events of getting a head and of getting tail by A and B respectively.

Number of trials in which the event A happens = 240

Number of trials in which the event B happens = 260

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \implies \: P(A) = \dfrac{number \: of \: trials}{total \: number \: of \: trials}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \implies \: P(A) = \dfrac{240}{500} = 0.48$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \implies \: P(B) = \dfrac{number \: of \: trials}{total \: number \: of \: trials}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \implies \: P(B) = \dfrac{260}{500} = 0.48$

• Probability : Probability is the uncertainty of occuring or happening of something

• Its widely used in every field such as physical sciences , commerce , biological sciences , medical sciences , weather forecasting.

• Experimental Approach : An operation which can produce some well defined outcomes.