Question

.A coin is tossed 500 times with the following frequencies of two outcomes:

Head : 240 times, tail: 260 times

Find the probability of occurrence of each of these events.​

Answer 1

No .of times the coin was tossed .i.e n(s) = 500

Event A = Heads

n(A) = 240

P(A) = n(A) / n(s)

= 240 / 500

= 12 / 25

Event B = Tails

n(B) = 260

P(B) = n(B) / n(s)

= 260 / 500

= 13 / 25

I hope it helps u dear friend ^_^♡♡

Answer 2

Answer:

okayy.armyy

Step-by-step explanation:

we know that a coin tossed 500 times the outcomes only can come head and tail

head come 240 times

and tail come 260 times

so first head comes

$= \frac{240}{500}$

$hence \: head \: comein \: 500times \: = \frac{12}{25}$

now , the tail come

$= \frac{260}{500}$

$hence \: the \: tail \: come \: in \\ \: 500 \: times= \frac{13}{25}$

hope u will like my answer :)).