Question

A coin is tossed 6 times, in how many throws can 4 heads and 2 tails be obtained?

a)24

b)18

c)15

d)10

Answer 1

Given that a coin is tossed 6 times.

Total possible combinations = 2^6 = 64.

(i)

Let A be the event of getting 4 heads and 2 tails.

⇒ C(6,4) * C(2,2)

⇒ 15 * 1

⇒ 15.

Therefore, the answer is 15 - Option(C).

(or)

{HHHHTT,HHHTHT,HHHTTH,HHTHHT,HHTHTH,HHTTHH,HTHHHT,HTHHTH,HTHTHH,HTTHHH,THHHHT,THHHTH,THHTHH,THTHHH,TTHHHH}.

⇒ Possible outcomes = 15

Hope it helps!