a coin is tossed 60 times with the frequencies : head 34 and tail 26 . if a coin is tossed at random. what is the probability of getting a head ?
Answers
Step-by-step explanation:
Total outcomes = 1000
Frequency of head = 455
Frequency of tails = 545
i) The probability of heads =\frac{\text {Number of time head drawn}}{\text {Total number of times tossed}}=
Total number of times tossed
Number of time head drawn
\begin{gathered}\begin{aligned} &=\frac{455}{1000} \\ &=0.455 \end{aligned}\end{gathered}
=
1000
455
=0.455
ii) Probability of tail =\frac{\text { Number of time tail drawn }}{\text { Total number of times tossed }}=
Total number of times tossed
Number of time tail drawn
\begin{gathered}\begin{array}{l}{=\frac{545}{1000}} \\ {=0.545}\end{array}\end{gathered}
=
1000
545
=0.545
In this question we were asked to find out the probability of all the ‘possible outcomes’. The ‘two possible outcomes’ while tossing a coin are occurrence of heads and occurrence of tails. Therefore, we have considered these two possibilities and calculated the result accordingly.
Answer:
Step-by-step explanation:
Total number of times the coin is tossed = 60 . <br> Number of times tails appear = 35. <br> Number of times heads appear = (60-35) = 25. <br> P(getting a head) = 25 ÷ 60 = 5 ÷ 12