Question

A Coin is Tossed 8 times. In How
ny
ways.
We
can
gets 5
head ​

Answer 1

Answer:

Explain the Question

Step-by-step explanation:

first

Answer 2

Answer:

You are choosing 3 tail results from the 8 events. This can be imagined as an 8-digit binary number composed of 3 zeros and 5 ones. How many different ways can we arrange 3 zeros in such a number?

This can also be imagined as 8 empty offices where three of them will be assigned. How many different ways can we put three indistinguishable triplets in 8 offices?

To choose 3 from 8 we reckon like so: There are 8 possibilities for the first “tail” (person to get an office); 7 for the second and 6 for third. And, in the end we do not care about the order of these assignments. The calculation goes like so:

(8 * 7 * 6) / (3 * 2) The more standard way to express this is:

8! / (5! * 3!) = 56

Similarly, choosing 5 heads from 8 coin tosses produces the same result. The calculation goes like this:

(8 * 7 * 6 * 5 * 4) / (5 * 4 * 3 * 2) The more standard way to express this is:

8! / (3! * 5!) = 56