Question

A coin is tossed 80 times with the following outcomes:head:35 times and tail: 45 times. In a single throw of a coin, if E is the event of getting a head, verify that P(E) + P(not E) =1

Answer 1

35÷80 + 45÷80=1
80÷80=1
the statement is justified

Answer 2

Answer:

Step-by-step explanation:

n (s) for head = 80

Let E be the event.

n(E) = 35

▪p (E) = 35÷ 80

= 7÷ 16

Now for tail n(S) = 80

Let E be event

So,

P( E) +p( not E)=

( 7÷16 ) + (1- 7÷16)

= (7÷16) +(9÷16)

= 7+9÷16

=16÷16

= 1

Hence ,p(E) +p(not E)=1