Question

a coin is tossed and a die is rolled simultaneously find the probability of event p of getting a head and no. less than 4​

Answer 1

Answer:

this is not the whole question

A coin is tossed and a die is thrown simultaneously :

P is the event of getting head and a odd number.

Q is the event of getting either H or T and an even number.

R is the event of getting a number on die greater than 7 and a tail.

S is the sample space.

is the full question

Step-by-step explanation:

ans= A coin is tossed and a die is thrown simultaneously.

S={H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6}

Thus n(S)=12

P is the event of getting head and an odd number.

P={H1,H3,H5}

Thus n(P)=3

Q is the event of getting either H or T and an even number.

Q={H2,H4,H6,T2,T4,T6}

Thus n(Q)=6

R is the event of getting a number greater than 7 and tail 1.

R={}

∴n(R)=0

is the answer

Answer 2

Answer:

In the case of the coin been tossed,. there is the probability of getting a head is 1 because a coin has only 2 sides, the opposite side is tail.

In the case of die, there is a probability of getting no. less than 4 is 3, that is, 1, 2 and 3.