Math, asked by ibrahimmo6003, 10 months ago

. A coin is tossed and a single 6-sided die is rolled. Find the probability of landing on the head side of
the coin and rolling a 3 on the die

Answers

Answered by Anonymous
9

Probability of head and 3 on a die is:

P( head and 3 ) = p(head )* P(3)

We multiply probabilities because we have 2 independent events.

We know that p(head) = 1/2

Also p(3) = 1/6

Then P( head and 3) = 1/2 * 1/6 = 1/12

Answered by ishika7968
3

 \huge\boxed{\boxed{\fcolorbox{white}{pink}{Answer}}}

When coin is tossed:

Sample spaces= {H,T}

Total outcomes= 2

Favourable outcomes= 1

 \Large\mathcal\green{Probability= \frac{Favourable\: outcomes}{Total\: outcomes}}

 \mathcal\pink{Substituting\: the\: values}

 \mathcal {P(Getting\: Head)= \frac{1}{2}}

When Die is rolled:

Sample spaces= {1,2,3,4,5,6}

Total outcomes= 6

Favourable outcomes= 1

 \Large\mathcal\green{Probability= \frac{Favourable\: outcomes}{Total\: outcomes}}

 \mathcal\pink{Substituting\: the\: values}

 \mathcal {P(Getting\: 3)= \frac{1}{6}}

 \mathcal\orange{Multiplying\: both\: probabilities}

 \Large\mathbb{ \frac{1}{2}×\frac{1}{6}}

 \Large\mathbb{\frac{1}{12}}

Hope it helps úh

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