Question

a coin is tossed in a dice is rolled simultaneously find the probability of getting a head for a tail and an odd number​

Answer 1

Answer:

ANSWER

A coin is tossed and a die is thrown simultaneously.

S={H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6}

Thus n(S)=12

P is the event of getting head and an odd number.

P={H1,H3,H5}

Thus n(P)=3

Q is the event of getting either H or T and an even number.

Q={H2,H4,H6,T2,T4,T6}

Thus n(Q)=6

R is the event of getting a number greater than 7 and tail 1.

R={}

∴n(R)=0

Hence, option C is correct.

Answer 2

Answer:

Hear is ur answer

Step-by-step explanation:

The coin and die are independent, so the probabilities of the two events can be multiplied. The probability of an odd number is 1/2, and the probability of a tail is also 1/2, so the probability of both occurring is the product, 1/4.

Thank me pls

Mark me as a brainiest