a coin is tossed n times the maximum value of n such that the probability of getting no head is greater than 1 by 16 is
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Answer:
n = 3.
Step-by-step explanation:
When you toss a coin one time, chances of no heads is 1/2.
When you tolls 2 times, no head chances = 1 /4 (You have 4 options, TT, TH, HT or HH)
=> with n tosses, chances of no heads is 1/(2^n)
(1/2^n) > (1/16)
=> 2^n < 16 (when fraction inequality changes the sign reverses)
=> n < 4.
So answer is tossing 3 times, you will have more probability of no heads.
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