Question

A coin is tossed successively three times. Find probability of getting exactly one head or two heads..

Experts plz answer step by step.....

Answer 1

Answer:

Probability of getting exactly one head or two head is 3/4.

Step-by-step explanation:

Given:

A coin is tossed successively three times.

To find: probability of getting exactly one head or two head.

We know that,

$Probability=\frac{Number\:of\:favorable\:outcome}{number\:of\:total\:outcome}$

Sample space of the given experiment =

{ (H , H , H) , (H , H , T) , (H , T , H) , (H , T , T) , (T , H , H) , (T , H , T) , (T , T , H) , (T , T , T) }

First we find probability of getting one head,

favorable outcome = { (H , T , T) , (T , H , T) , (T , T , H) }

Probability = 3/8

Second we find probability of getting two head,

favorable outcome = { (H , H , T) , (H , T , H) , (T , H , H) }

Probability = 3/8

Probability of getting exactly one head or two head = 3/8 + 3/8 = 6/8 = 3/4

Therefore, Probability of getting exactly one head or two head is 3/4.

Answer 2

Answer:

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Step-by-step explanation:

Probability of getting exactly one head or two head is 3/4.

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