Question

a coin is tossed three times. find the probability of the following events. (A getting at least two heads (B getting exactly two heads (C getting at most one head​

Answer 1

1.P(E)=N(S)/N(E)

=2/3

2. 2/3

31/3

Answer 2

Answer:

OUTCOMES = (HHH) , (HHT) , (HTH) , (HTT) , (TTT) , (TTH) , (THH) , (THT)

Probability= Number of favourable outcomes/Total number of outcomes

A) P(getting atleast 2 heads) = 4/8

                                                =1/2

B) P(getting exactly 2 heads) =3/8

C) P(getting atmost one head)=3/8

Step-by-step explanation: