A coin is tossed three times . than the probabitily that at least on tail occurs is
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0
Answer:
3/4 if one coin is tossed
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27
Answer:
Step-by-step explanation:
7/8
Step-by-step explanation:
p = P(tail) = 1/2
q = P(head) = 1 - p = 1/2.
The r.v. X is B(3, 1/2).
Then P(obtaining at least 1 tail in 3 tosses of one coin) = P(X≥1) = P(X = 1) + P(X = 2) + P(X = 3) = 1 - P(X = 0) =
1−(3/0)(1/2)^0(1/2)^3
=1−1×1×(1/2)^3
=1−1/8=7/8
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