A coin is tossed three times then the probability
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Answered by
1
Answer:
Is this a question.................
Answered by
1
Answer:
Sample space: {
HHH,HTH,THH,TTH
HHT,HTT,THT,TTT
}
Total number of possible outcomes=8
(1) A getting at least two heads
P(A)=P(getting two heads)+P(getting 3 heads)
=
8
3
+
8
1
(using formula=P(event)=
Total no. of possible outcomes
No. of favourable outcomes
P(A)=
8
4
=
2
1
∴P(A)=
2
1
(2) B: getting exactly two heads
P(B)=3/8
(3) C: getting almost one head
P(C)=P(getting no head)+P(getting 1 head)
=
8
1
+
8
3
=
8
4
=
2
1
P(C)=
2
1
.
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