Question

A coin is tossed three times.what is the probability of getting at least one tail?

Answer 1

$\bold \orange{ \: hey \: mate}$


A coin can only get heads or tails. So you have 1/2 chance of getting either heads or tails.

Well simplify tails to T and heads to H.

The possibilities are:

T H H

H T H

H H T

T T H

T H T

H T T

T T T

H H H

As you can see, there is only one cenario in throwing all the coins where there isnt a tails. In tha scenario, you’d need all three coins to be heads. The chances are for one given coin to be heads is 1/2, so the chance for all three to have that same result would be (1/2)^3 ( as a probability tip, anytime you must consider that the result something must happen AND somethin else must happen, you multiply the odds of those two things happening; the chamces that the first coin is heads and the second coin is heads and the third coin is heads equates to 1/2*1/2*1/2 = (1/2)^3 = 1/8 )

So you have a 7/8 chance that you will have at least one tails. If you want a % answer, just multiply 7/8 * 100.

$\bold \red{ \: i \: hope \: it \: helps}$

Answer 2

Answer:

$\frac{7}{8}$

Step-by-step explanation:

To find the probability of getting at least one tail in Tossing a coin three time,let the event is A

we know that

Probability =

$\frac{favourable \: outcome}{total \: outcome}$

Total outcomes:8

these are

{TTT,TTH,THT,THH,HTT,HTH,HHT,HHH}

Favourable outcome of getting at least one tail:7

these are :{TTT,TTH,THT,THH,HTT,HTH,HHT}

Probability of getting at least one tail

$P(E)= \frac{7}{8}$

Hope it helps you.