Question

a coin is tossed twice, find the probability of appearing (i) both heads (ii) one head (iii) at least one head (iv) both tails

Answer 1

1) 2÷4

2) 1÷4

3)3÷4

4)2÷4

Answer 2

P(E)=no of favourable outcomes /

Total no of outcomes

Here,Total Outcomes=>HH,HT,TH,TT

=4

1)P(getting 2 heads) =1/4

2)P(getting one head=2/4

3)P(getting atleast one head)=3/4

4)P(getting both tails)=1/4