A coin is tossed twice find the probability of getting 1 at least 1 tail 2) almost
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hey mate! here is your ans..
to toss a coin twice is same as to toss 2 coins simultanuously
so passible outcomes are (tt)(hh)(ht)(th)
so n(s)=4
now probability of getting at least 1 tail = 3/4
to toss a coin twice is same as to toss 2 coins simultanuously
so passible outcomes are (tt)(hh)(ht)(th)
so n(s)=4
now probability of getting at least 1 tail = 3/4
hp780:
in 2nd question i think something is missing
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