a coin is tossed twice find the probability of getting to heads
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2/4
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The probability of getting atleast one head is HH,HT that is 2/3.the total chances n(s)=3
n(e)=2
probability p=n(e)/n(s)=2/3
n(e)=2
probability p=n(e)/n(s)=2/3
I dont understand can you expain me vai
There are 3 chances HH,HT,TT.If we want to get atleast one head then we can choose probability 2/3
I understand now thanks for helping me vai
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yes i ask ouestion plz solve that 2 ouestion i have to understand help me
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