Question

A coin is tossed twice what is a probability of getting at least one head

Answer 1

total no of event is 4.i.e (h,h) (h,t) (t,h) (t,t)
no. of events having at least one head
is 3
therefore p(getting at least one head)= 3/4

Answer 2

S = { HH,HT,TH,TT }

n(S) = { 4 }

Let A be the event of atleast one head.

A = { HH,HT,TH }

n(A) = { 3 }

Therefore,

P(A) = n(A)÷n(S)

= 3 upon 4

Therefore, the probability of getting atleast one H is 3 upon 4

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