Question

A coin is tossed two times find the probability of getting at least one head​

Answer 1

GIVEN:

• Favourable outcomes = 1+1 = 2
• Total outcomes = 2+2 = 4

FIND:

• Probability of getting one head

SOLUTION:

here,

We know that

$\rm \to P(E_1) = \frac{favourable \: outcomes}{total \: outcomes}$

where,

• Favourable outcomes = 2
• Total outcomes = 4

So,

$\rm \to P(E_1) = \frac{2}{4}$

$\rm \to P(E_1) = \frac{ \cancel2}{ \cancel4}$

$\rm \to P(E_1) = \frac{ 1}{ 2}$

Hence, Probability of getting head atleast one time is $\rm\frac{1}{2}$

Answer 2

Answer:

SOLUTION:

here,

We know that

where,

Favourable outcomes = 2

Total outcomes = 4

So,

Hence, Probability of getting head atleast one time is