Question

A coin just remains on disc rotating a steady rate of 180 rpm A coin is kept at distance of 2 cm from axis of rotation the coefficient of friction between coin and disc is g= 9.8 ms square

Answer 1

Answer:

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Answer 2

Thus the coefficient of friction between  coin and disc is μ = 0.724

Explanation:

Given data:

r = 2 cm = 0.02 m

Speed of rotation = 180 rpm

ω = 2πN / 60  = 2 π x 180 / 60 = 18.84 rad/s

F = mrω^2 = μmg

μ = rω^2 / g = 0.02 x 18.84^2 / 9.8

μ = 0.724

Thus the coefficient of friction between  coin and disc is μ = 0.724