Physics, asked by XxSIDHARTHxX, 9 months ago

A coin kept inside water (meu = 4/3) when viewed from air in a vertical direction, appears to be raised by 2.0 mm. Find the depth of the coin in water.​

Answers

Answered by Anonymous
6

Answer:

Then apparent depth is x-2 mm. Hence, depth of coin in water is 8 mm

Answered by MrBrainlyBrilliant
42

Question :-

A coin kept inside water (mew = 4/3) when viewed from air in a vertical direction, appears to be raised by 2.0 mm. Find the depth of the coin in water.

To Find :-

Depth of the coin in water.

Answer :-

Given, meu = 4/3,

shift = 2.0 mm.

Let real depth be x mm.

Therefore,

Apparent depth = x/meu

= x/(4/3)

= 3x/4

Shift = real depth - apparent depth.

= x - 3x/4 = x/4

Given,

Shift = x/4 = 2.0 mm

Therefore,

x = 8 mm

Thus, depth of coin in water = 8 mm.

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