A coin kept inside water (meu = 4/3) when viewed from air in a vertical direction, appears to be raised by 2.0 mm. Find the depth of the coin in water.
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6
Answer:
Then apparent depth is x-2 mm. Hence, depth of coin in water is 8 mm
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42
Question :-
A coin kept inside water (mew = 4/3) when viewed from air in a vertical direction, appears to be raised by 2.0 mm. Find the depth of the coin in water.
To Find :-
Depth of the coin in water.
Answer :-
Given, meu = 4/3,
shift = 2.0 mm.
Let real depth be x mm.
Therefore,
Apparent depth = x/meu
= x/(4/3)
= 3x/4
Shift = real depth - apparent depth.
= x - 3x/4 = x/4
Given,
Shift = x/4 = 2.0 mm
Therefore,
x = 8 mm
Thus, depth of coin in water = 8 mm.
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