A coin kept on a horizontal rotating disc has a centre at a distance of from the axis of rotation of the disc. If the coefficient of friction between the disc and the coin is , then the angular speed of the disc at which the coin is about to slip off is (use g= 10 )
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Answer:
N=mg
fs=mgr
=
4
mg
f
s
=mrw
2
4
mg
=(m)(0.1)(w
2
)
w
2
=
0.4
g
w=
4
100
w
2
=5rads/sec
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