Physics, asked by sunitagurav20121, 8 months ago

a coin kept on horizontal rotating disc has a center at a distance of 12.5 cm from the axis of rotation of the disc.if the coefficient of between the disc and the coin is 0.2 then the angular speed of the disc at which the coin is about to slip of is ​

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Answered by anandubala0837
0

Answer:

A coin kept on a horizontal rotating disc has its center at a distance of 0.1 m from the axis of the rotating disc. If the coefficient of friction between the coin and the disc is 0.25; find the angular speed of disc at which the coin would be about the slip off (Given: g = 9.8 m/s)

December 26, 2019avatar

Srujan Vaishu

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ANSWER

N=mg

fs=mgr

=

4

mg

f

s

=mrw

2

4

mg

=(m)(0.1)(w

2

)

w

2

=

0.4

g

w=

4

100

w

2

=5rads/sec

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