Question

A coin lies at the bottom of a trough in which the height of water is 20 cm. Find how much it seems to be raised from the bottom. The refractive index of water is 4/3.​

Answer 1

Explanation:

Answer

Virtual Depth of the coin is 15−3.75=11.25cm

Virtual Depth of the coin is 15−3.75=11.25cm Refractive index =

Virtual Depth of the coin is 15−3.75=11.25cm Refractive index = virtual depth

Virtual Depth of the coin is 15−3.75=11.25cm Refractive index = virtual depthreal depth

=15/11.25=1.33

Answer 2

RI=
apparent depth
real depth
​


Substituting,
3
4
​
=
apparentdepth
12
​


Therefore, apparent depth=
4
12×3
​
=9

The height by which it appears to be raised is 12−9=