Question

a coin lies at the bottom of the trough the depth of the water is u=4/3 in it is 15 cm find its Apparent depth​

Answer 1

Here,

Refractive index=Real Depth/Apparent depth

4/3=15cm/apparent depth

apparent depth=45/4cm=11.25cm

Answer 2

The apparent depth of the coin is 11.25 cm.

Explanation:

The ratio of real depth to the apparent depth of an object at the bottom of water is equal to the refractive index.

Here, the real depth at the bottom depth of the water is 15 cm, d = 15 cm

Refractive index of water, $n=\dfrac{4}{3}$

Let d' is the apparent depth of the coin. So,

$n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{15}{(4/3)}\\\\d'=11.25\ cm$

So, the apparent depth of the coin is 11.25 cm.

Learn more,

A coin lies at the bottom of the trough the depth of the water is u=4/3 in it is 15 cm find its Apparent depth​

https://brainly.in/question/1111895