Question

a coin of mass 25g is pushed on a table
. The coin start moving at speed

of
2
5cms-1 and stopFind the force of friction exerted by the table on the coin?​

Answer 1

Answer:

33 is the answer please mark me as brilliant

Answer 2

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Correct Question:-

• A coin of mass 25g is pushed on a table The coin start moving at speed of 25cms-1 and stop at 5s . Find the force of friction exerted by the table on the coin?

$\text{\large\underline{\purple{Given:-}}}$

• Mass of the coin 25 g = 0.025 kg
• Mass of the coin 25 g = 0.025 kgInitial velocity (u) = 25 cm/s = 0.25 m/s
• Final velocity (v)= o[ stops]
• Time taken(t) = 5 s

$\text{\large\underline{\red{To\:Find:-}}}$

• Frictional force exerted by the table.

$\text{\large\underline{\pink{Solution:-}}}$

• Force is given by the formula

• F AP/t .... (1)

$\text{\large\underline{\orange{Here,}}}$

• F=force
• AP= change in momentum
• t time taken

$\text{\large\underline{\green{We know that,}}}$

• ∆P= Pբ - Pí
• ∆p = Mv - mu
• ∆p = m(v-u)

Now let's substitute the values in the above equation,

• AP 0.025 (0 - 0.25)
• AP-0.00625 kg m/s

Now,

• F= AP/t

Now let's substitute the values in the above equation 1,

• F-0.00625/ 5
• F=- 0.00123 N

"The negative sign denotes that the denotes that the frictional force is opposite to the direction of motion".

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