Physics, asked by Anonymous, 2 months ago

A coin of mass 25g is pushed on a table. The coin starts moving at speed of 25m/s and stops on 5 sec. Find the frictional force exerted by the table​

Answers

Answered by divyanka1421
3

Answer:

F = -0.00125N

explanation:

coin of mass (u) = 25g

time (t) = 5sec

speed of coin (v) = 25m/s

v = u + at

0 = 25 + 5a

- 5a = 25

a = 25/5

a = -5

the frictional force (F) = ma

F = 25/1000×(-5)/100

F = -0.00125N

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