a coin placed at a depth of 15cm in a beaker containing water. the refractive index of water is 4/3. calculate the height through which the image of the coin is raised.
Answers
Refractive index of the water, μw = 4/3
Real depth at which the coin is places = 12 cm
Shift in the image = ?
Shift = real depth × (1 - 1/μ)
Shift = 12 × (1 - 3/4)
R = 12/4 = 3cm
Explanation:
As, you need to find the Apparent height through which the coin is raised and not the shift in the height therefore, the solution goes hereby...
Given,
Real depth = 15cm
Refractive index = 4/3
Apparent depth = ?
refractive index = real depth/ Apparent depth
therefore,
Apparent depth = refractive index × real depth
= 4/3 × 15
= 45/4 = 11.25 cm
Hight through which the coin is raised =
(15 - 11.25)cm = 3.75 cm
Answer : 3.75cm
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