Question

a coin placed at a depth of 15cm in a beaker containing water. the refractive index of water is 4/3. calculate the height through which the image of the coin is raised.

Answer 1

Refractive index of the water, μw = 4/3

Real depth at which the coin is places = 12 cm

Shift in the image = ?

Shift = real depth × (1 - 1/μ)

Shift = 12 × (1 - 3/4)

R = 12/4 = 3cm

Answer 2

Explanation:

As, you need to find the Apparent height through which the coin is raised and not the shift in the height therefore, the solution goes hereby...

Given,

Real depth = 15cm

Refractive index = 4/3

Apparent depth = ?

refractive index = real depth/ Apparent depth

therefore,

Apparent depth = refractive index × real depth

= 4/3 × 15

= 45/4 = 11.25 cm

Hight through which the coin is raised =

(15 - 11.25)cm = 3.75 cm

Answer : 3.75cm

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