Question

A coin placed at the bottom of a beaker appears to be raised by 4.0 cm. If the refractive Index of water is 4/3 find the depth of water in the beaker.​

Answer 1

Answer:

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Explanation:

Let Real depth = x

∵ Refractive Index, μ = Real depth/Apparent depth

⇒ 4/3 = x/x – 4

⇒ 4x – 16 = 3x

∴ x = 16 cm.