Question

A coin placed at the bottom of a beaker containing a liquid of refractive index

8

5 appears to be raised by

2.4 cm. Find the depth of the liquid in the beaker.​

Answer 1

Answer:

3 CM

explanation :

Refractive index of the water, μw = 4/3

Real depth at which the coin is places = 12 cm

Shift in the image = ?

Shift = real depth × (1 - 1/μ) Shift =

12 × (1 - 3/4) R =

12/4 =

3cm