Math, asked by panditbali12345, 10 months ago

a coin placed in a beaker containing water appears at a depth of 3 cm from the water surface what is the real depth of the coin ?
The refractive index of water is 4 by 3​

Answers

Answered by iiTibs
3

Answer:

12

Step-by-step explanation:

3 x 4 = 12

Answered by munnahal786
0

Answer:

We see apparent depth instead of the real depth when we see the bottom of the water jar from the surface of the water , this is because of the refraction of light . When the light travels from denser to rarer medium , light bends away from the normal . So for the observer the light seems to be coming from the point above the surface and therefore the apparent depth of the surface is little less than the actual depth .

apparent depth = 3cm

refracting index of the medium of the observer n₁ = 1

refracting index of the medium of the coin , n₂ = 4/3

apparent depth × n₂= real depth × n₁

3×4/3= real depth ×1

real depth = 4 cm

Hence the real depth of the coin is 4cm.

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