Question

A coin placed under a glass slab of refractive index 1.5, appears to be raised by 0.8cm. find the real thickness of glass slab. ​

Answer 1

Answer:

2.4 cm

Explanation:

Refractive index of the glass block, μg = 1.5 Shift in the image = 8mm or 0.8 cm Thickness of glass block or real depth =? Shift = Real depth × (1 - 1/μ) 0.8= R × (1 - 1/1.5) R = 0.8 x 1.5/0.5 = 2.4 cm

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Answer 2

Answer:

2.4 cm

Explanation:

let real depth( or thickness of glass slab) = x cm

Since the coin seems to be raised by 0.8 cm, apparent depth = (x-0.8)cm

the refractive index of glass with respect to air = real depth / apparent depth

1.5 = x/x-0.8

on cross multiplying,

1.5x - 1.2 = x

1.5x - x = 1.2

0.5x = 1.2

x = 1.2/0.5 = 12/5 = 2.4 cm

Hence the real thickness of glass slab = 2.4cm