A coin purse contain 5c,10c and 25c coins. The number of 10c is 3times as many 5c coins is two more than the 10c , If the Total Value of each contens is 490 pesos, How many each kind of coins are there in purse
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Let +a+ = number of 5 c coins
Let +b+ = number of 10 c coins
Let +c+ = number of 25 c coins
given:
(1) 5a+10b+25c+= 490
(2) b = 3a
(3) c= b+2
Substitute (2) and (3) into (1)
(1) 5 x (b/3) + 10b + 25 x (b+2) = 490
(1) 5 x (b/3) + 10b + 25b + 50 = 490
(1) (5/3) x b + 35b = 440
Multiply both side by 3
(1) 5b + 105b = 1320
(1) 110b = 1320
(1) b = 12
(2) a = b/3
(2) a = 12/3
(2) a = 4
and
(3) c = b+2
(3) c = 12 + 2
(3) c = 14
There are 4 of the 5 c coins
There are 12 of the 10 c coins
There are 14 of the 25 c coins
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