Question

A coin shows up a head 150 times when it is tossed 240 times. If this coin is tossed again, find
the probability of getting a:
(a) head
(b) tail​

Answer 1

Answer:

Step-by-step explanation:

as it is tossed 240 times , the possibility of getting a -

a ) head is 150/240

b ) tail is 240 - 150 = 90

90/240

HOPE IT HELPS

Answer 2

GIVEN :-

• total no of coin tossed = 240 times

• total no of head comes = 150 times

TO FIND :-

• probability of coming heads and tails

SOLUTION :-

so as we know

$\implies \boxed{\rm{p \: (a) = \dfrac{no \: of \: favourable \: events}{total \: no \: of \: events} }}$

so for head

no of heads come = 150

total no of coin tossed = 240

so ,

$\implies \rm{p \: (heads) = \dfrac{150}{240} }$

$\implies \rm{p \: (heads) = \dfrac{15}{24} }$

$\implies \rm{ \bf{p \: (heads) = \dfrac{5}{8} }}$

no for tails

no of tails = total no of coin tossed - total no of heads

total no of tails = 240 - 150

total no of tails = 90

total no of coin tossed = 240

now ,

$\implies \rm{p \: (tails) = \dfrac{90}{240} }$

$\implies \rm{p \: (tails) = \dfrac{9}{24} }$

$\implies \rm{ \bf{p \: (tails) = \dfrac{3}{8}} }$

HENCE ,

$\implies \boxed{ \boxed{\rm{ \:p \: (h) = \dfrac{5}{8} \: , \: p \: (t) = \dfrac{3}{8} } }}$