Question

A coin tossed 3 times. The probability of
getting head once and tail 2 times is
A) 118
B) 114
O 0) 318
D) 1/2
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Answer 1

Answer:

answered

Step-by-step explanation:

Sample space: {  

HHH,HTH,THH,TTH

HHT,HTT,THT,TTT

​  

}

Total number of possible outcomes=8

(1) A getting at least two heads

P(A)=P(getting two heads)+P(getting 3 heads)

=  

8

3

​  

+  

8

1

​  

 

(using formula=P(event)=  

Total no. of possible outcomes

No. of favourable outcomes

​  

 

P(A)=  

8

4

​  

=  

2

1

​  

 

∴P(A)=  

2

1

​  

 

(2) B: getting exactly two heads

P(B)=3/8

(3) C: getting almost one head

P(C)=P(getting no head)+P(getting 1 head)

=  

8

1

​  

+  

8

3

​  

=  

8

4

​  

=  

2

1

​  

 

P(C)=  

2

1

​  

.

Answer 2

Answer:

$\frac{3}{8}$