Question

А A coin tossed twise. Find the probability of getting at least one head​

Answer 1

Answer:

3/4

Step-by-step explanation:

because coin tossed twice so

(H, H) ( T, T) ( H, T) ( T, H)

according to question at least one head

so probability is 3 by 4

Answer 2

Step-by-step explanation:

1) \frac{1}{2}

2

1

2)\frac{3}{4}

4

3

3)\frac{3}{4}

4

3

When two coins are tossed>

Outcomes: {HH,HT,TH,TT}=4

(1)Exactly one head

Favorable events = {HT,TH}=2

Probability = \frac{\text{Favorable outcomes}}{\text{Total outcomes}}

Total outcomes

Favorable outcomes

So, probability of getting exactly one head : \frac{2}{4}

4

2

: \frac{1}{2}

2

1

(2)at least one head

At least one head means there should be 1 or more heads .

Favorable outcome = {HH,TH,HT}=3

So, probability of getting at least one head : \frac{3}{4}

4

3

(3)at most one head

At most one head means there should 1 or less than one or no heads.

Favorable outcome = {TT,TH,HT}=3

So, probability of getting at most one head : \frac{3}{4}

4

3

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