Math, asked by manotiwari1994, 1 year ago

A coir carpet is placed in a hall so as to leave a border of 2 m wide all around the hall. if the hall is 30 m by 26 m, find the area of the carpet and also the area uncovered by the carpet​

Answers

Answered by pandiyanj
7

Answer:

Step-by-step explanation:

Area of room = 14 × 10 = 140m2

Area of carpet = 14-1 × 10 -1 = 117m2

Area remains uncovered = 140 - 117 = 23m2

Hope it helps u !

Answered by JeanaShupp
13

The area of the carpet is 572 square meters and the area uncovered by the carpet​ is 208 square meters.

Explanation:

Formula:  Area of rectangle = Length x width

Given : The dimensions of the hall = 30 m by 26 m

Area of floor of the hall = 30 x 26 = 780  square meters

A coir carpet is placed in a hall so as to leave a border of 2 m wide all around the hall.

So , the  dimensions of the carpet =  (30-2(2)) m by (26-2(2)) m = 26 m by 22 m

Area of carpet= 26 x 22 = 572 square meters

Area uncovered = Area of floor of the hall - Area of carpet

= 780-572  square meters

= 208 square meters.

∴ The area of the carpet is 572 square meters and the area uncovered by the carpet​ is 208 square meters.

#Learn more :

A school has a hall which is 22m long and 15.5 m broad. A carpet is laid inside the hall leaving all around a margin of 7.5 cm from the walls. Find the area of the carpet and the area of the carpet and the area of the strip left uncovered.

https://brainly.in/question/14411307

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