A college awarded 38 medals in football, 15 in basketball and 20 in cricket. If these medals went to a total of 38 and only three men got medals in all the three sports, how many received medals in exactly two of the three sports?
Answers
Answered by
11
Answer:
I think the answer is 38
Step-by-step explanation:
38+15+20+3-X=38
76-X=38
76-38=X
38=X
Answered by
5
Answer:
HEY DIDU...HERE IS UR ANSWER.....
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Step-by-step explanation:
____________________
.
Let F,B,C be the sets of students who received medals in football, basketball, and cricket respectively.
n(F)=38
n(B)=15
n(C)=20
n(F∪B∪C)=58
n(F∩B∩C)=3
We know, n(F∪B∪C)=n(F)+n(B)+n(C)−n(F∩B)−n(B∩C)−n(F∩C)+n(F∩B∩C)
n(F∩B)+n(B∩C)+n(C∩F)=73−58+3=18
the number of students who received medals in exactly two of the three
sports is,
n(F∩B)+n(B∩C)+n(C∩F)−3×n(F∩B∩C)=18−9=
#MAHAK.....
LUV U DIDU
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