Math, asked by rithikasherina, 9 months ago

A college schedules lectures of 9 professors. 3
professors every day, till all possible combinations
are exhausted. If no combination of professors is
ever repeated on any day, then how many days will
each of professor have to come?​

Answers

Answered by amitnrw
5

Given : A college schedules lectures of 9 professors. 3  professors every day, till all possible combinations  are exhausted. no combination of professors is  ever repeated on any day

To find :   how many days will  each of professor have to come?

Solution:

Total professors = 9

Professors every day = 3

Number of was 3 professors can be selected =  ⁹C₃

= 9!/6!3!

= 9 * 8  * 7 /( 3 * 2 * 1)

= 84

Each day 3 professors come

in 84 Days total Visit of professors  = 84 * 3  

There are 9 professors

One professor have to come  = 84 * 3 / 9

= 28 Days

28 Days each of professor have to come

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Answered by nancychaterjeestar29
0

Answer:

28 Days

Step-by-step explanation:

Solution:

Total professors = 9

Professors every day = 3

Number of was 3 professors can be selected =  ⁹C₃

= 9!/6!3!= 9 * 8  * 7 /( 3 * 2 * 1)

= 84

Each day 3 professors come

in 84 Days total Visit of professors  = 84 * 3  

There are 9 professors

One professor have to come  = 84 * 3 / 9

= 28 Days

28 Days each of professor have to come

#SPJ2

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