A colloidal solution is subjected to an electric field. The particles move towards anode. The coagulation of same sol is studied using NaCl, BaCl₂ and AlCl₃ solutions. The order of their coagulation power should be –
(a) NaCl > BaCl₂ > AlCl₃
(b) BaCl₂ > AlCl₃ > NaCl
(c) AlCl₃ > BaCl₂ > NaCl
(d) BaCl₂ > NaCl > AlCl₃
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the answer should be C)
because the particles moves towards anode ,so particls of colloidal solution must posses negative charge .
therefore to coagulate them the positively charged particle will be used.
according to Hardy Schulze rule : the coagulation power is directly proportional to the charge on the coagulating particle .
so greater the charge on the coagulating particle higher is the coagulation pawer
thus C) Is write answer
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