Biology, asked by ashbrunda2002, 9 months ago

A colour blind Man is known to be heterozygous for sickle cell anemia amd pku the proportion od his sperm carrying recessive allels of all three disorders would be

Answers

Answered by StunningBabe27
5

\huge\mathcal{\underline{\underline{\red{Answer:-}}}}

<body bgcolor=pink><font color=blue>

Colourblindness is an X linked recessive disease whereas Phenylketonuria (PKU) is an autosomal recessive trait.

Since Mr. Christopher is a carrier for PKU, this means, only one allele for PKU is present in the autosome. He is colorblind this means that he has the genotype XcY.

The sperms produced by the man will be half carrying X chromosome and half carrying Y chromosome. This means that 50% of the sperms will be carrying the defective allele for colorblindness. Out of these 50% sperms, half of these will be having the defective allele for phenylketonuria as well i.e. 25%.

So, the correct answer is '25%'.

<marquee behaviour-move><font color="purple pink"><h1>Thanks♡</ht/><marquee>

Answered by GoldenShaded
1

 \huge\purple{ \:\:\:\:\:\:\underline{\underline{ \blue{✰ᗩᑎՏᗯᗴᖇ✰}}}}

Colourblindness is an X linked recessive disease whereas Phenylketonuria (PKU) is an autosomal recessive trait.

Since Mr. Christopher is a carrier for PKU, this means, only one allele for PKU is present in the autosome. He is colorblind this means that he has the genotype XcY.

The sperms produced by the man will be half carrying X chromosome and half carrying Y chromosome. This means that 50% of the sperms will be carrying the defective allele for colorblindness. Out of these 50% sperms, half of these will be having the defective allele for phenylketonuria as well i.e. 25%.

So, the correct answer is '25%'.

Similar questions