a colourless solution of compound A gives white precipitate beats when treated with sodium hydroxide solution the white precipitate dissolves in excess of sodium hydroxide solution the clear solution does obtained when treated with hydrogen sulphide gas gives white precipitate see and say ABC
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Answer:
Aluminum bromide (A) reacts with sodium hydroxide to give a white precipitate of aluminum hydroxide.
AlBr
3
+3NaOH→
whiteppt
Al(OH)
3
↓
+3NaBr
The precipitate dissolves in excess of NaOH to form sodium meta aluminate which is (C).
Al(OH)
3
+NaOH→
sodiummetaaluminate
Na[AlO
2
]
+2H
2
O
Sodium meta aluminate does not give precipitate with hydrogen sulphide.
When sodium meta aluminate is boiled with ammonium chloride, the precipitate of aluminum hydroxide is formed.
Aluminum bromide reacts with silver nitrate to form yellow precipitate of silver bromide.
AlBr
3
+3AgNO
3
→
yellowprecipitate
3AgBr
+Al(NO
3
)
3
Explanation:
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yes
Explanation:
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