A combination lock uses three distinctive numbers between 0 and 39 inclusive. How many different ways can a sequence of three numbers be selected?
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Hi there!
∵ Ye have 40 choices i.e. 0 - 39 n' There's no repetition.
→ For the First number you can use all of the digits.
→ For the second number you can only use 39.
[ you already used one and repetition is not allowed. ]
→ For the third number you can only use 38
[ you already used 2 numbers. ]
& This process will continues to Go On....... till we reach 0
Therefore,
40 × 39 × 38 = 59, 280
Hence, The required answer is :-
In 59, 280 ways a sequence of three numbers be selected.
Hope it helps! :)
∵ Ye have 40 choices i.e. 0 - 39 n' There's no repetition.
→ For the First number you can use all of the digits.
→ For the second number you can only use 39.
[ you already used one and repetition is not allowed. ]
→ For the third number you can only use 38
[ you already used 2 numbers. ]
& This process will continues to Go On....... till we reach 0
Therefore,
40 × 39 × 38 = 59, 280
Hence, The required answer is :-
In 59, 280 ways a sequence of three numbers be selected.
Hope it helps! :)
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