Question

A combination of parallel plate capacitors is maintained at a certain potential difference.When a 3 mm thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between the pl

Answer 1

Answer:

5

Explanation:

Capacitance in parallel plate capacitor is given by

C=

d

ϵ

0

A

Now introducing a slab of thickness t, the capacitance C

′

is

C

′

=

d

′

−t(1−1/K)

ϵ

0

A

Now q=CV as it remains same so,

C=C

′

d

ϵ

0

A

=

d

′

−t(1−1/K)

ϵ

0

A

d=d

′

−t(1−1/K)

d=d+2.4×10

−3

−3×10

−3

(1−1/K)

On solving we get

K=5

Hence correct answer is B.