A combination of resistors has 3 resistors in series. Four such sets are connected in parallel .If each resistor is 4 ohm , total resistance of the combination is
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for a series total resitance would be 4+4+4=12 ohm
for a parallel total resistance would be (1/12)+(1/12)+(1/12)+(1/12)=1/3 ohm or 0.3333 ohm
for a parallel total resistance would be (1/12)+(1/12)+(1/12)+(1/12)=1/3 ohm or 0.3333 ohm
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3 resistors in of 4 ohm in ech wire
total resistance in each wire =4+4+4=12
now,
total resistance in all = (1/12)+(1/12)+(1/12)+(1/12)= 4/12=1/3=3ohm in all
total resistance in each wire =4+4+4=12
now,
total resistance in all = (1/12)+(1/12)+(1/12)+(1/12)= 4/12=1/3=3ohm in all
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