A commercial sample of hydrogen peroxide is labelled as 10 volume its strength in gram per litre is
Answers
Answered by
1
Answer:
1 mL of 10 volume H
2
O
2
= 10 mL of O
2
at NTP.
2(2+32) =68 g
2H
2
O
2
→2H
2
O+
22400 mL at NTP
O
2
22400 mL of O
2
at NTP are obtained from 68 g of H
2
O
2
10 mL of O
2
at NTP are obtained from
22400
68
×10 g of H
2
O
2
10 mL of O
2
at NTP are obtained from
2240
68
g of H
2
O
2
1 ml of H
2
O
2
solution contains
2240
68
g of H
2
O
2
.
100 ml of H
2
O
2
solution contains
2240
68
×100=3% of H
2
O
2
.
Similar questions