Math, asked by adetolalydia, 5 months ago

a committee 4 people is to be chosen from 5 married couples. find in how many ways the committee can be chosen
1).If everyone is equally eligible
2).If the committee should include at least one woman

Answers

Answered by ShravaniG17
0

Answer:

answer is down

Step-by-step explanation:

option is down

Answered by Anonymous
7

Answer:

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Step-by-step explanation:

5 married couples = 5 Men and 5 Women

Case 1: Everyone is equally eligible

=> No. of ways to chose 4 people out of 10 = 10C4 = 210

Case 2: At least one women

=> total no. of ways - those ways in which no woman is selected

No. of ways in which no woman is selected = no. of ways in which only men are selected = 5C4 = 5

=> 210 - 5 = 205

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