Math, asked by rounick3980, 1 year ago

A committee is to be formed comprising 7 members such that there is a simple majority of men and at least 1 woman. The shortlist consists of 9 men and 6 women. In how many ways can this committee be formed?
A.4914
B.3630
C.3724
D.3824

Answers

Answered by anupamchaudhury12
0

Answer:

Ans = 4914

Step-by-step explanation:

Number of members of the committee = 7

Condition is, Men should have the majority and at least 1 woman should be present.

Number of man >= 4     [to maintain a majority]

and, Number of women <=3 and >=1     [to maintain majority as well as a single women should be present]

Given, Total men = 9 & Total Women = 6

Now, we have to select men out of 9 men and women from 6 nos. or women.

So, possible cases of forming the committee are as follows:

Case 1: 6 men and 1 woman

Number of ways committee can be formed = Selecting 6 men out of 9 men + Selecting 1 woman out of 6 woman

= 9C6 x 6C1 = 504

Case 2: 5 men and 2 woman

Number of ways committee can be formed = 9C5 x 6C2 = 1890

Case 3: 4 men and 3 woman

Number of ways committee can be formed = 9C4 x 6C3 = 2520

If we go further, the condition of majority of men will be violated.

∴ Total no. of ways the committee can be formed is

= Case 1 + Case 2 + Case 3

=  504 + 1890 + 2520

= 4914 = Ans

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